indexOf method Null safety
- E element,
- [int start = 0]
override
The first index of element
in this list.
Searches the list from index start
to the end of the list.
The first time an object o
is encountered so that o == element
,
the index of o
is returned.
final notes = <String>['do', 're', 'mi', 're'];
print(notes.indexOf('re')); // 1
final indexWithStart = notes.indexOf('re', 2); // 3
Returns -1 if element
is not found.
final notes = <String>['do', 're', 'mi', 're'];
final index = notes.indexOf('fa'); // -1
Implementation
@override
int indexOf(E element, [int start = 0]) => _base.indexOf(element, start);