Trace.current constructor Null safety

Trace.current(
  1. [int level = 0]
)

Returns the current stack trace.

By default, the first frame of this trace will be the line where Trace.current is called. If level is passed, the trace will start that many frames up instead.

Implementation

factory Trace.current([int level = 0]) {
  if (level < 0) {
    throw ArgumentError('Argument [level] must be greater than or equal '
        'to 0.');
  }

  var trace = Trace.from(StackTrace.current);
  return LazyTrace(() {
    // JS includes a frame for the call to StackTrace.current, but the VM
    // doesn't, so we skip an extra frame in a JS context.
    return Trace(trace.frames.skip(level + (inJS ? 2 : 1)),
        original: trace.original.toString());
  });
}